Skip to main content
Home
Pimath

Menu EN

  • Home
  • 🌐 EN
    • 🇪🇸 ES
    • 🇫🇷 FR
    • 🇮🇹 IT
    • 🇵🇹 PT
  • About Me
  • Theory and Exercises
    • Algebra
    • Linear Algebra
    • Elementary Functions
    • Analytic Geometry
    • Mathematical Analysis
User account menu
  • Log in

Breadcrumb

  1. Home

Radicals: Definition, Properties and Examples

Profile picture for user Pimath
By Pimath, 18 April, 2026

Radicals: definition, existence conditions, fundamental properties, simplification, operations and rationalisation. Examples and step-by-step solved exercises.


Table of Contents

  • Definition of a radical
  • Existence conditions
  • Fundamental properties
  • Simplifying radicals
  • Multiplication and division
  • Addition and subtraction
  • Powers of radicals
  • Rationalising the denominator
  • Radicals with variables
  • Radical equations

Definition of a radical

The nth root of a real number \(a\) is the number \(b\) such that raising it to the nth power gives back \(a\).

Definition
Given \( n \in \mathbb{N} \), \( n \geq 2 \) and \( a \in \mathbb{R} \), the nth root of \( a \) is defined as the real number \( b \) satisfying: \[ b = \sqrt[n]{a} \quad \Longleftrightarrow \quad b^n = a \]

The number \( n \) is the index of the radical, and \( a \) is the radicand.

Square Root

By convention, when \( n = 2 \) the index is omitted:

\[ \sqrt{a} = \sqrt[2]{a} \]

The square root always returns the principal non-negative value and is defined only for \( a \geq 0 \). The following identity is important:

\[ \sqrt{a^2} = |a| \] Warning. In general \( \sqrt{a^2} \neq a \). For instance, \( \sqrt{(-3)^2} = \sqrt{9} = 3 \neq -3 \).

nth Root: parity of the index

Index \( n \)Radicand \( a \)Result
Even\( a > 0 \)a unique positive real value exists (principal root)
Even\( a = 0 \)\( \sqrt[n]{0} = 0 \)
Even\( a < 0 \)does not exist in \( \mathbb{R} \)
Oddany \( a \in \mathbb{R} \)a unique real value exists, with the same sign as \( a \)

Examples
\( \sqrt[3]{-8} = -2 \) since \( (-2)^3 = -8 \)
\( \sqrt[4]{16} = 2 \) (principal root)
\( \sqrt[5]{-32} = -2 \) since \( (-2)^5 = -32 \)

Existence conditions

A radical is a real number only when the radicand satisfies the following conditions, which depend on the parity of the index.

Existence condition
\[ \sqrt[n]{a} \in \mathbb{R} \quad \Longleftrightarrow \quad \begin{cases} a \geq 0 & \text{if } n \text{ is even} \\ a \in \mathbb{R} & \text{if } n \text{ is odd} \end{cases} \] Examples
\( \sqrt{x-3} \) exists \(\iff\) \( x-3 \geq 0 \) \(\iff\) \( x \geq 3 \)
\( \sqrt[3]{x-3} \) exists for every \( x \in \mathbb{R} \)
\( \sqrt{x^2-4} \) exists \(\iff\) \( x \leq -2 \) or \( x \geq 2 \)

Fundamental properties

The following properties hold whenever all expressions are defined in the real numbers (in particular, for even indices, all radicands must be non-negative).

PropertyFormula
Radical of a power\( \sqrt[n]{a^m} = a^{m/n} \) (with \( a \geq 0 \) if \( n \) is even)
Power of a radical\( (\sqrt[n]{a})^m = \sqrt[n]{a^m} \)
Nested radical\( \sqrt[m]{\sqrt[n]{a}} = \sqrt[mn]{a} \)
Reduction to a common index\( \sqrt[n]{a} = \sqrt[kn]{a^k} \) for \( k \in \mathbb{N}, k \geq 1 \)
Index simplification\( \sqrt[kn]{a^k} = \sqrt[n]{a} \)

Connection with fractional exponents

\[ \sqrt[n]{a^m} = a^{m/n} \]

Simplifying radicals

A radical is in simplified form when the radicand contains no factors that are perfect powers of the index — that is, no factors that can be extracted as whole numbers.

Method for simplification

  1. Factor the radicand into primes (or into factors with explicit exponents).
  2. Write each exponent as a multiple of \( n \) plus a remainder \( r \) with \( 0 \leq r < n \).
  3. Extract from the radical any part whose exponent is a multiple of the index.

\[ \sqrt[n]{a^{qn+r}} = a^q \sqrt[n]{a^r}, \quad 0 \leq r < n \quad (a \geq 0 \text{ if } n \text{ even}) \] Examples
\( \sqrt{72} = \sqrt{36 \cdot 2} = 6\sqrt{2} \)
\( \sqrt[3]{54} = \sqrt[3]{27 \cdot 2} = 3\sqrt[3]{2} \)
\( \sqrt{x^5} = x^2 \sqrt{x} \) for \( x \geq 0 \)
\( \sqrt[3]{a^8} = a^2 \sqrt[3]{a^2} \)

Reduction to a common index

To combine radicals with different indices, use the least common multiple (LCM) of the indices.

Example
\( \sqrt{2} = \sqrt[6]{2^3} = \sqrt[6]{8} \)
\( \sqrt[3]{3} = \sqrt[6]{3^2} = \sqrt[6]{9} \)

Multiplication and division

Properties (for defined expressions)
\[ \sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}, \qquad \frac{\sqrt[n]{a}}{\sqrt[n]{b}} = \sqrt[n]{\frac{a}{b}} \quad (b > 0) \] Warning. These properties hold only when all radicands satisfy the existence conditions. Examples
\( \sqrt{3} \cdot \sqrt{12} = \sqrt{36} = 6 \)
\( \sqrt[3]{4} \cdot \sqrt[3]{2} = \sqrt[3]{8} = 2 \)
\( \frac{\sqrt{50}}{\sqrt{2}} = \sqrt{25} = 5 \)
\( \sqrt{2} \cdot \sqrt[3]{2} = \sqrt[6]{2^5} = \sqrt[6]{32} \)

Addition and subtraction

Only like radicals — those sharing the same index and the same radicand — can be added or subtracted.

Like radicals
\( p\sqrt[n]{a} \pm q\sqrt[n]{a} = (p \pm q)\sqrt[n]{a} \) Examples
\( 3\sqrt{2} + 5\sqrt{2} = 8\sqrt{2} \)
\( \sqrt{12} + \sqrt{27} = 2\sqrt{3} + 3\sqrt{3} = 5\sqrt{3} \)
\( \sqrt{8} - \sqrt{2} + \sqrt{18} = 2\sqrt{2} - \sqrt{2} + 3\sqrt{2} = 4\sqrt{2} \)

Powers of radicals

\[ (\sqrt[n]{a})^m = \sqrt[n]{a^m} = a^{m/n} \quad (a \geq 0 \text{ if } n \text{ even}) \]

Square of a binomial involving radicals

\[ (\sqrt{a} + \sqrt{b})^2 = a + 2\sqrt{ab} + b \]
\[ (\sqrt{a} - \sqrt{b})^2 = a - 2\sqrt{ab} + b \]

Product of conjugate expressions

\[ (\sqrt{a} + \sqrt{b})(\sqrt{a} - \sqrt{b}) = a - b \]

Rationalising the denominator

Rationalising the denominator means rewriting a fraction so that no radicals appear in the denominator, by multiplying both numerator and denominator by a suitable factor.

Case 1 — Denominator with a single radical

\[ \frac{b}{\sqrt[n]{a}} = \frac{b \cdot \sqrt[n]{a^{n-1}}}{a} \quad (a \geq 0 \text{ if } n \text{ even}) \] Examples
\[ \frac{3}{\sqrt{5}} = \frac{3\sqrt{5}}{5} \]
\[ \frac{1}{\sqrt[3]{2}} = \frac{\sqrt[3]{4}}{2} \]

Case 2 — Binomial denominator with square roots

\[ \frac{c}{\sqrt{a} \pm \sqrt{b}} = \frac{c(\sqrt{a} \mp \sqrt{b})}{a - b} \] Examples
\[ \frac{4}{\sqrt{3} + \sqrt{2}} = \frac{4(\sqrt{3} - \sqrt{2})}{3-2} = 4\sqrt{3} - 4\sqrt{2} \]
\[ \frac{1}{1 + \sqrt{5}} = \frac{\sqrt{5} - 1}{5-1} = \frac{\sqrt{5}-1}{4} \]

Case 3 — Denominator with cube roots (sum or difference)

The sum and difference of cubes identities are used:

\[ x^3 + y^3 = (x+y)(x^2 - xy + y^2) \qquad x^3 - y^3 = (x-y)(x^2 + xy + y^2) \]

For \( \frac{1}{\sqrt[3]{a} - \sqrt[3]{b}} \) (setting \( x = \sqrt[3]{a} \), \( y = \sqrt[3]{b} \)):

\[ \frac{1}{\sqrt[3]{a} - \sqrt[3]{b}} = \frac{\sqrt[3]{a^2} + \sqrt[3]{ab} + \sqrt[3]{b^2}}{a - b} \] Example
\[ \frac{1}{\sqrt[3]{2} - 1} = \frac{\sqrt[3]{4} + \sqrt[3]{2} + 1}{2 - 1} = \sqrt[3]{4} + \sqrt[3]{2} + 1 \]

Radicals with variables

Absolute value in simplification

For an even index (\( n = 2k \)): \( \sqrt[2k]{x^{2k}} = |x| \)
For an odd index: \( \sqrt[2k+1]{x^{2k+1}} = x \) Examples
\( \sqrt{x^2} = |x| \)
\( \sqrt[4]{x^4} = |x| \)
\( \sqrt{x^6} = |x^3| \)
\( \sqrt[3]{x^3} = x \)

Domain of expressions involving several radicals

The domain is the intersection of the existence conditions of all radicals present.

Example
\( f(x) = \sqrt{x+2} + \sqrt{4-x} \)
Domain: \( x \geq -2 \) and \( x \leq 4 \) \(\Rightarrow\) \( [-2, 4] \)

Radical equations

To solve a radical equation, follow these steps:

  1. Determine the domain (existence conditions of all radicals).
  2. Isolate one radical (if possible).
  3. Raise both sides to the appropriate power.
  4. Solve the resulting algebraic equation.
  5. Check each candidate solution in the original equation and verify it belongs to the domain (to discard any extraneous solutions).

Warning. Raising both sides to a power may introduce extraneous solutions. Verification is mandatory.

Example — even index

\( \sqrt{2x-1} = x-2 \)

Domain: \( x \geq \frac{1}{2} \) and \( x-2 \geq 0 \) \(\Rightarrow\) \( x \geq 2 \).

Squaring both sides: \( 2x-1 = (x-2)^2 \Rightarrow x^2 - 6x + 5 = 0 \Rightarrow x=1 \) or \( x=5 \).

Check: \( x=1 \) does not belong to the domain → extraneous solution.
\( x=5 \): \( \sqrt{10-1} = 3 \) and \( 5-2=3 \) → verified.

Solution: \( x=5 \)

Example — two radicals

\( \sqrt{x+5} - \sqrt{x} = 1 \)

Domain: \( x \geq 0 \).

Isolate: \( \sqrt{x+5} = \sqrt{x} + 1 \).

Square both sides: \( x+5 = x + 2\sqrt{x} + 1 \Rightarrow 4 = 2\sqrt{x} \Rightarrow x=4 \).

Check: \( \sqrt{9} - \sqrt{4} = 3-2=1 \) → correct.

Solution: \( x=4 \)


Your feedback is important to us! Leave a comment and help us improve this content. Thank you!

Feedback

Support us with a Like:
Or, share:

Tags

  • Algebra

Support us with a Like:
Or, share:

Copyright © 2026 | Pimath | All Rights Reserved